Talk:Sums of powers

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I have found these

Latest comment: 1 year ago1 comment1 person in discussion

(4x^{7}+108y^{7})^{3}+(4x^{7}-108y^{7})^{3}=(2x^{3})^{7}+(6xy^{2})^{7}

above is outcome of the following formula

(4^{n}x^{6n+1}+108^{n}y^{6n+1})^{3}+(4^{n}x^{6n+1}-108^{n}y^{6n+1})^{3}=(2x^{3})^{6n+1}+(6xy^{2})^{6n+1}

Potato Imaginator (talk) 02:56, 14 August 2024 (UTC)Reply

About a new formula

Latest comment: 10 months ago1 comment1 person in discussion

An independent researcher from Bangladesh has proposed a power-sum formula similar to that of Faulhaber's but without relying on any Bernoulli numbers, should it be added here in this page? Noorwastaken (talk) 20:23, 19 September 2025 (UTC)Reply