Edge Rewrite
// HTMLRewriter · presentation

This page was redesigned at the edge.

Cloudflare fetched the original article and streamed it through HTMLRewriter to apply an entirely new visual system without rebuilding the source page.

Jump to content

Crout matrix decomposition

From Wikipedia, the free encyclopedia
(Redirected from Crout's method)

In linear algebra, the Crout matrix decomposition is an LU decomposition which decomposes a matrix into a lower triangular matrix (L), an upper triangular matrix (U) and, although not always needed, a permutation matrix (P). It was developed by Prescott Durand Crout. [1]

The Crout matrix decomposition algorithm differs slightly from the Doolittle method. Doolittle's method returns a unit lower triangular matrix and an upper triangular matrix, while the Crout method returns a lower triangular matrix and a unit upper triangular matrix.

So, if a matrix decomposition of a matrix A is such that:

A = LDU

being L a unit lower triangular matrix, D a diagonal matrix and U a unit upper triangular matrix, then Doolittle's method produces

A = L(DU)

and Crout's method produces

A = (LD)U.

Implementations

[edit]

C implementation:

void crout(double const **A, double **L, double **U, int n) {
	int i, j, k;
	double sum = 0;

	for (i = 0; i < n; i++) {
		U[i][i] = 1;
	}

	for (j = 0; j < n; j++) {
		for (i = j; i < n; i++) {
			sum = 0;
			for (k = 0; k < j; k++) {
				sum = sum + L[i][k] * U[k][j];	
			}
			L[i][j] = A[i][j] - sum;
		}

		for (i = j; i < n; i++) {
			sum = 0;
			for(k = 0; k < j; k++) {
				sum = sum + L[j][k] * U[k][i];
			}
			if (L[j][j] == 0) {
				printf("det(L) close to 0!\n Can't divide by 0...\n");
				exit(EXIT_FAILURE);
			}
			U[j][i] = (A[j][i] - sum) / L[j][j];
		}
	}
}

Octave/Matlab implementation:

   function [L, U] = LUdecompCrout(A)
        
        [R, C] = size(A);
        for i = 1:R
            L(i, 1) = A(i, 1);
            U(i, i) = 1;
        end
        for j = 2:R
            U(1, j) = A(1, j) / L(1, 1);
        end
        for i = 2:R
            for j = 2:i
                L(i, j) = A(i, j) - L(i, 1:j - 1) * U(1:j - 1, j);
            end
            
            for j = i + 1:R
                U(i, j) = (A(i, j) - L(i, 1:i - 1) * U(1:i - 1, j)) / L(i, i);
            end
        end
   end

References

[edit]
  1. Press, William H. (2007). Numerical Recipes 3rd Edition: The Art of Scientific Computing. Cambridge University Press. pp. 50–52. ISBN 9780521880688.