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Bisacurone

From Wikipedia, the free encyclopedia
(Redirected from C15H24O3)
Bisacurone
Names
Preferred IUPAC name
(6S)-6-[(1R,4S,5S)-4,5-Dihydroxy-4-methylcyclohex-2-en-1-yl]-2-methylhept-2-en-4-one
Identifiers
3D model (JSmol)
ChemSpider
UNII
  • InChI=1S/C15H24O3/c1-10(2)7-13(16)8-11(3)12-5-6-15(4,18)14(17)9-12/h5-7,11-12,14,17-18H,8-9H2,1-4H3/t11-,12+,14-,15-/m0/s1
    Key: QJOWFYQIUZMPRY-NEBZKDRISA-N
  • C[C@@H](CC(=O)C=C(C)C)[C@H]1C[C@@H]([C@@](C=C1)(C)O)O
Properties
C15H24O3
Molar mass 252.354 g·mol−1
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Bisacurone is a chemical compound with the molecular formula C15H24O3 which has been isolated from turmeric (Curcuma longa). In vitro, it has several effects including anti-inflammatory, anti-oxidant, and anti-metastatic properties.[1]

References

[edit]
  1. Sun, Dong-Il; Nizamutdinova, Irina Tsoy; Kim, Young Min; Cai, Xing Fu; Lee, Jung Joon; Kang, Sam Sik; Kim, Yeong Shik; Kang, Ki Mun; Chai, Gyu Young; Chang, Ki Churl; Kim, Hye Jung (2008). "Bisacurone inhibits adhesion of inflammatory monocytes or cancer cells to endothelial cells through down-regulation of VCAM-1 expression". International Immunopharmacology. 8 (9): 1272–1281. doi:10.1016/j.intimp.2008.05.006. PMID 18602074.