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Talk:Nemytskii operator

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Latest comment: 7 months ago by Yoneda-Emma in topic Redundant Sections

In the section of the Boundless Theorem it may be added, that there exists a more general form where one concludes from , , that the Nemytskii operator is a bounded and continuous map from to .

This may belong to another article; but I have not found a better place yet.

Jjh1993 (talk) 11:16, 8 November 2014 (UTC)Reply

Redundant Sections

[edit]

This article, in its current form, gives three very similar definitions of the operator in question in its first three sections, which differ from each other only in slight details - I don't feel I am familiar enough with functional analysis to judge which one should be preferred, but surely the article should only give a single generalized definition and derive everything else from there? Yoneda-Emma (talk) 16:14, 8 January 2026 (UTC)Reply