Template:Math theorem/testcases

Basic Usage (math_statement=...)

{{Math theorem|{{#parsoid

{{Math theorem}}

Theorem—$\Gamma (D(f),{\mathcal {O}}_{X})=A[f^{-1}]$ for every f in A.

{{Math theorem/sandbox}}

Theorem. $\Gamma (D(f),{\mathcal {O}}_{X})=A[f^{-1}]$ for every f in A.

With Optional Theorem Name and Note

{{Math theorem|math_statement=The area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. |name=[[Pythagorean Theorem]] |note=This is a note}}

{{Math theorem}}

Pythagorean Theorem (This is a note)—The area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.

{{Math theorem/sandbox}}

Pythagorean Theorem (This is a note). The area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.

With Optional Proof Parameter

{{Math theorem|expand_proof=yes |math_statement=The area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. |name=[[Pythagorean Theorem]] |proof=Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. |proof_name=My Proof}}

{{Math theorem}}

Pythagorean Theorem—The area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.

{{Math theorem/sandbox}}

Pythagorean Theorem. The area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.

My Proof. Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.∎