Edge Rewrite
// HTMLRewriter · presentation

This page was redesigned at the edge.

Cloudflare fetched the original article and streamed it through HTMLRewriter to apply an entirely new visual system without rebuilding the source page.

// request.cf · coarse context

A page that knows where it met you.

Only coarse request metadata is shown. This demo does not display or persist visitor IP addresses.

Country
US
Cloudflare location
CMH
Connection
HTTP/2
Language
Not provided

Ray ID: a21fb0b98e8a879c

Jump to content

Talk:Operator algebra

Page contents not supported in other languages.
Add topic
From Wikipedia, the free encyclopedia
Latest comment: 3 months ago by Linas in topic Examples

Examples

[edit]

It would be nice to have at least one example of an Operator Algebra. Most of the other pages on mathematical objects list a few examples. CarlFeynman (talk) 23:06, 4 May 2011 (UTC)Reply

There seem to be some examples now. I suppose more would be better. linas (talk) 17:40, 4 April 2026 (UTC)Reply

Non-commutative?

[edit]

This page says "Operator algebras are in general non-commutative rings" Whereas, the page about rings say rings have to have the property that their operators are commutative. What gives? —Preceding unsigned comment added by 76.23.104.212 (talk) 20:44, 13 May 2011 (UTC)Reply

In general, a ring's product is not necessarily commutative. Some authors, the ones who will only be talking about commutative rings, include commutativity in the definition for convenience. It's just a matter of convention. The phrase "non-commutative ring" refers to a ring whose product is not assumed to be commutative. However, I think the Wikipedia page on rings should not include commutativity since the "standard" definition does not. 70.30.23.131 (talk) 16:53, 5 June 2014 (UTC)Reply

Extremely bad introduction

[edit]

The first two paragraphs of the article are as follows

"In functional analysis, an operator algebra is an algebra of continuous linear operators on a topological vector space with the multiplication given by the composition of mappings.

"The results are phrased in algebraic terms, while the techniques are highly analytic. Although it is usually classified as a branch of functional analysis, it has direct applications to representation theory, differential geometry, quantum statistical mechanics, quantum information, and quantum field theory."

This writing is inappropriate for several reasons.

1. When the first sentence describes only a mathematical concept ("an operator algebra"), nobody knows what Wikipedia is talking about when it then begins the next paragraph with "The results". The results of what??? The article has not stated what it is talking about.

Most Wikipedia readers will not understand this unless they are mathematicians. Most Wikipedia readers have no idea what the word "results" refers to here.

2. The second sentence in the second quoted paragraph is just as bad, if not worse:

"Although it is usually classified as a branch of functional analysis, it has direct applications to ..."

Almost nobody reading Wikipedia will have the slightest idea what the word "it" means each time it is used in this sentence.

(Helpful hint: When using a pronoun, make sure it has an antecedent.)2600:1700:E1C0:F340:DD66:DEDF:A0A1:935D (talk) 20:39, 24 October 2018 (UTC)Reply

Is it better now? – Tea2min (talk) 08:20, 25 October 2018 (UTC)Reply