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// Workers AI · dad joke modeWhat did the Cantic octagonal tiling say? It was tiled to meet you.

From Wikipedia, the free encyclopedia
Cantic octagonal tiling
Cantic octagonal tiling
Poincaré disk model of the hyperbolic plane
TypeHyperbolic uniform tiling
Vertex configuration3.6.4.6
Schläfli symbolh2{8,3}
Wythoff symbol4 3 | 3
Coxeter diagram =
Symmetry group[(4,3,3)], (*433)
DualOrder-4-3-3 t12 dual tiling
PropertiesVertex-transitive

In geometry, the tritetratrigonal tiling or shieldotritetragonal tiling is a uniform tiling of the hyperbolic plane. It has Schläfli symbol of t1,2(4,3,3). It can also be named as a cantic octagonal tiling, h2{8,3}.

Dual tiling

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Uniform (4,3,3) tilings
Symmetry: [(4,3,3)], (*433) [(4,3,3)]+, (433)
h{8,3}
t0(4,3,3)
r{3,8}1/2
t0,1(4,3,3)
h{8,3}
t1(4,3,3)
h2{8,3}
t1,2(4,3,3)
{3,8}1/2
t2(4,3,3)
h2{8,3}
t0,2(4,3,3)
t{3,8}1/2
t0,1,2(4,3,3)
s{3,8}1/2
s(4,3,3)
Uniform duals
V(3.4)3 V3.8.3.8 V(3.4)3 V3.6.4.6 V(3.3)4 V3.6.4.6 V6.6.8 V3.3.3.3.3.4
*n33 orbifold symmetries of cantic tilings: 3.6.n.6
Symmetry
*n32
[1+,2n,3]
= [(n,3,3)]
Spherical Euclidean Compact Hyperbolic Paracompact
*233
[1+,4,3]
= [3,3]
*333
[1+,6,3]
= [(3,3,3)]
*433
[1+,8,3]
= [(4,3,3)]
*533
[1+,10,3]
= [(5,3,3)]
*633...
[1+,12,3]
= [(6,3,3)]
*∞33
[1+,∞,3]
= [(∞,3,3)]
Coxeter
Schläfli
=
h2{4,3}
=
h2{6,3}
=
h2{8,3}
=
h2{10,3}
=
h2{12,3}
=
h2{∞,3}
Cantic
figure
Vertex 3.6.2.6 3.6.3.6 3.6.4.6 3.6.5.6 3.6.6.6 3.6..6

Domain
Wythoff 2 3 | 3 3 3 | 3 4 3 | 3 5 3 | 3 6 3 | 3 ∞ 3 | 3
Dual
figure
Face V3.6.2.6 V3.6.3.6 V3.6.4.6 V3.6.5.6 V3.6.6.6 V3.6.∞.6

See also

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References

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  • John H. Conway, Heidi Burgiel, Chaim Goodman-Strauss, The Symmetries of Things 2008, ISBN 978-1-56881-220-5 (Chapter 19, The Hyperbolic Archimedean Tessellations)
  • "Chapter 10: Regular honeycombs in hyperbolic space". The Beauty of Geometry: Twelve Essays. Dover Publications. 1999. ISBN 0-486-40919-8. LCCN 99035678.
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