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1912 Paris–Roubaix

From Wikipedia, the free encyclopedia
(Redirected from 1912 Paris-Roubaix)

1912 Paris–Roubaix
Race details
Dates7 April 1912
Stages1
Distance266 km (165 mi)
Winning time8h 30' 00"
Results
  Winner  Charles Crupelandt (FRA)
  Second  Gustave Garrigou (FRA)
  Third  Maurice Léturgie (FRA)
 1911
1913 

The 1912 Paris–Roubaix was the 17th edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 7 April 1912 and stretched 266 km (165 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Charles Crupelandt from France.[2]

Results

[edit]
Final results (1–10)[2]
Rank Cyclist Time
1  Charles Crupelandt (FRA) 8h 30' 00″
2  Gustave Garrigou (FRA) +0' 00″
3  Maurice Léturgie (FRA) +0' 00″
4  Octave Lapize (FRA) +0' 00″
5  Odiel Defraye (BEL) +0' 00″
6  Jules Masselis (BEL) +0' 00″
7  Charles Deruyter (BEL) +0' 00″
8  Joseph Van Daele (BEL) +6' 00″
9  Eugène Platteau (BEL) +6' 00″
10  Paul Deman (BEL) +6' 00″

References

[edit]
  1. "17th Paris – Roubaix, 1912". bikeraceinfo. Retrieved 5 March 2015.
  2. 1 2 "1912  » 17th Paris – Roubaix". ProCyclingStats. Retrieved 5 March 2015.